Question

Q.5
A solid toy is in the form of a right circular cylinder with a hemispherical
shape at one end and a cone at the other end. Their common diameter is 4.2 cm
and the height of the cylindrical and conical portions are 12 cm and 7 cm
respectively. Find volume of solid toy. (T = )
02​

Answer 1

Given -

• Height of conical portion(h1) = 7 cm

• Height of cylindrical portion = (h2) = 12 cm
• Diameter of cylinder, cone and hemisphere = 4.2 cm
• So, radius = 4.2/2 = 2.1 cm

To find -

The volume of solid toy

Solution -

Volume of solid toy = Volume of conical portion +Volume of cylindrical portion + Volume of hemispherical portion.

Volume of solid toy = 1/3πr²h1 + πr²h2 + 2/3πr³

Volume of solid toy = 1/3πr²(h1 + 3 × h2 + 2r)

Volume of solid toy = 1/3×π ×(2.1)² (7 + 3 × 12 + 2 × 2.1)

= 1/3 × π × (2.1)² ( 7 + 36 + 4.2)

= 1/3 × π × (2.1)² ( 43 + 4.2)

= 1/3 × π × (2.1)² (47. 2)

= 1/3 × 22/7 × 2.1 × 2.1 × 47.2

= 1/3 × 0.7 × 0.3 × 47.2

= 3 × 0.7 × 0.3 × 42.7

= 218.064 cm³

$\therefore$ The volume of solid toy is 218.064 cm³

______________________________________

Answer 2

$\huge{\boxed{\rm{\red{Question}}}}$

A solid toy is in the form of a right circular cylinder with a hemispherical shape at one end and a cone at the other end. Their common diameter is 4.2 cm and the height of the cylindrical and conical portions are 12 cm and 7 cm respectively. Find volume of solid toy. (T = 2 )

$\huge{\boxed{\rm{\red{Answer}}}}$

$\large{\boxed{\sf{Given \: that}}}$

• Height of cylindrical portion = 12 cm.

• Height of conical portions = 7 cm.

• Diameter of cone , hemisphere and cylinder = 4.2 cm.

$\large{\boxed{\sf{We \: know \: that}}}$

• Radius = Diameter / 2

• Value of diameter is given.

• Hence,

• Radius = 4.2 / 2 cm

• Radius = 2.2 cm

$\large{\boxed{\sf{To \: find}}}$

• Volume of Solid toy.

$\large{\boxed{\sf{Solution}}}$

• Volume of solid toy =

$\large{\boxed{\sf{Full \: solution}}}$

$\large\purple{\texttt{According to the question}}$

$\large\purple{\texttt{We know that,}}$

☆ Volume of solid toy = Volume of colonial portion + Volume of cylindrical portion + Volume of hemispherical portion.

$\implies$ Volume of solid toy = 1/3πr² h1 +πr² h2 + 2/3πr³

$\implies$ Volume of solid toy = 1/3 × π × (2.1)² ( 7 + 3 × 12 + 2 × 2.1 )

$\implies$ Volume of solid toy = 1/3 × π × (2.1)² × ( 7 + 36 + 4.2 )

$\implies$ Volume of solid toy = 1/3 × π × (2.1)² × ( 43 + 4.2 )

$\implies$ Volume of solid toy = 1/3 × π × (2.1)² × 47.2

$\implies$ Volume of solid toy = 1/3 × 22/7 × 2.1 × 2.1 × 47.2

$\implies$ Volume of solid toy = 1/3 × 0.7 × 0.3 × 47.2

$\implies$ Volume of solid toy = 3 × 0.7 × 0.3 × 47.2

$\implies$ Volume of solid toy = 218.064 cm³

$\large\purple{\texttt{Hence 218.064³is the volume of solid toy}}$

$\large{\boxed{\boxed{\underbrace{\sf{218.064³ \: is \: the \: answer}}}}}$

Hope it's helpful !

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