Question

Q.5 An object is placed at a distance of 12cm in front of a concave mirror .it forms a real image four times larger than the object , calculate the distance of the image from the mirror. Required question​

Answer 1

Answer:

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→ v = - 48 cm .

Step-by-step explanation :-

We have,

→ Object distance = 12 cm .

∴ u = - 12 cm .[ Since, object is placed in front of mirror ] .

And,

→ It forms a real image four times larger than the object .

∴ m = - 4 . [ Since, it forms a real image. So, magnification will be in minus ] .

To find :-

→ The distance of the image from mirror ( v ) .

Now,

We know that :-

$m \times \frac{ - v}{u}$

$- 4 = \frac{ - v}{ - 12}$

$- v = - 4 \times - 12$

$= - v = - 48cm$

Answer 2

$\huge\red{\mid{\fbox{\sf{\huge \: A᭄ɴsᴡᴇʀ࿐}}\mid}}$

$\small\mathbb{SOLUTION :–}$

$\tt→ \frac{ h_{o}}{ h_{i} } = \frac{ - v}{u}$

• u = -12 [ it is -ve because the object is real ]

$→ \tt\frac{ h_{o}}{ h_{i} } = \frac{4}{1}$

$\tt→ \frac{ - v}{u} = \frac{4}{1}$

$\tt→ \frac{ - v}{ - 12} = \frac{4}{1}$

$\tt→ \frac{ \cancel- v}{ \cancel- 12}$

→ v = 4 × 12v=

→ v = 48v=48

$\small\mathbb{ HENCE :–}$

• The distance of the image from the mirror is 48 cm

• And the nature of the image is :-

• Virtual.
• Large in size.
• Erect.

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