Question

Q.5 An object is placed at a distance of 12cm in front of a concave mirror .it forms a real image four times larger than the object , calculate the distance of the image from the mirror. Required question​

Answer 1

Answer:

$\huge \sf {\orange {\underline {\pink{\underline {❥︎A᭄ɴsᴡᴇʀ࿐ :−}}}}}$

Given :–

u = 12cm

It forms a real image four times larger than the object.

To Find :–

Calculate the distance of the image from the mirror.

Solution :–

Here we use magnification formula :–

$\sf→ \frac{ h_{o}}{ h_{i} } = \frac{ - v}{u}$

u = -12 [ it is -ve because the object is real ]

$→ \sf\frac{ h_{o}}{ h_{i} } = \frac{4}{1}$

$\sf→ \frac{ - v}{u} = \frac{4}{1}$

$\sf→ \frac{ - v}{ - 12} = \frac{4}{1}$

$\sf→ \frac{ \cancel- v}{ \cancel- 12}$

→ v = 4 × 12v=

→ v = 48v=48

Hence,

The distance of the image from the mirror is 48 cm

And the nature of the image is :-

Virtual.

Large in size.

Erect.