Question

Q.5 Attempt any one subquestion from the following.
1) In a right angle triangle, the difference between areas of squares drawn on
perpendicular sides of triangles is 7 sq.cm., and the area of square drawn on
hypotenuse is 25 sq.cm. Find sides of triangle.​

Answer 1

Answer:

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Step-by-step explanation:

The relation between side lengths of a right triangle is:

a2+b2=c2a2+b2=c2

a and b are the lengths of the perpendicular sides, and c is the length of the hypotenuse.

Given the lengths of the hypotenuse and one right side, the length of the other right side will be:

a=c2−b2−−−−−−√a=c2−b2

Putting the given lengths in this equation:

a=252–72−−−−−−√=625–49−−−−−−√=24cma=252–72=625–49=24cm.

The area of the right triangle will be:

A=a∗b2=24∗72=84cm2A=a∗b2=24∗72=84cm2