Question

Q.5 Consider a point charge +q placed at the origin and another point charge -2q placed at a
distance of 9 m on x-axis from the charge +q. Determine the point between the two charges at
which electric potential is zero.​

Answer 1

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Answer 2

Answer:

The distance of the point, which has zero electric potential is 3 m  right from +q and 6 m left from the -2q charge.

Explanation:

• The matter's physical property helps it experience a change or force when it is placed in an electric field or magnetic field, which is known as a charge.
• It can be a positive charge or negative charge.
• The work needed to be done to bring a unit charge against the electric field from a reference point (i.e, earth or ground) to a specified point, is called electric potential.
• The S.I unit of electric potential being volts or joules per coulomb.
• The expression of the electric potential is,

                                                            $v=k\frac{q}{r}$

where, k = constant

            q = charge

             r = distance of separation

Step-1:

Let the point P be placed at a distance of x meters placed on the right side from the +q charge and (9-x) meters on the left side from the -2q charge.

Step-2:

The total electric potential at point P is said to be zero.

∴ V = 9×10⁹ Nm²/coulomb (q/x - 2q/(9-x)) = 0

                        ∴       $\frac{q}{x} =\frac{2q}{(9-x)}$

Step-3:

Thus we get,

           (9-x) = 2x

∴ x = 3 meters

Thus the point P is placed at 3 meters right from +q charge and 6 meters left from -2q charge.