Question

Q. 5: Derive an expression for the kinetic energy of an object.​

Answer 1

Answer:

Ambarish shakal sharirik anarkali word karna

shariful Sharma

Explanation:

shajahan

Answer 2

Answer:

Consider a body of mass "m" moving with an initial velocity "u".

A constant force "F" acts on it and the velocity changes to "v".

Let "s" be the distance covered and "a" be the constant acceleration

We know that 

v² - u² = 2as

s = \frac{v^{2} - u ^{2} }{2a}2av2−u2 

We know that ,

Work done = Force(F) × displacement (s)

F = ma 

W = ma ×\frac{v^{2} - u ^{2} }{2a}2av2−u2 

["a" gets cancelled ] 

W = m ×\frac{v^{2} - u ^{2} }{2}2v2−u2 

= \frac{1 }{2}21 m[v² - u² ]

When , initial velocity , u = 0

W = \frac{1 }{2}21 mv²

K.E = Work done

= \frac{1 }{2}21 mv²