Question

Q.5) Find the area of triangle whose vertices are
A(5,8), B(5,0) C(1,0)​

Answer 1

Answer:

please check the answer

ok.

Answer 2

The area of the triangle is 16 square units.

Step-by-step explanation:

Given : Triangle whose vertices are  A(5,8), B(5,0) C(1,0)​.

To find : The area of triangle ?

Solution :

The area of the triangle is given by,

$A=|\dfrac{1}{2}[{x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)}]|$

Here, $x_1 =5, y_1 = 8, x_2 = 5, y_2 = 0\text{ and } x_3 = 1, y_3 = 0.$

Substitute in the formula,

$A=|\dfrac{1}{2}[{5(0-0) + 5(0-8) + 1(8-0)}]|$

$A=|\dfrac{1}{2}[{5(0)+ 5(-8) + 1(8)}]|$

$A=|\dfrac{1}{2}[{0-40+8}]|$

$A=|\dfrac{1}{2}[{-32}]|$

$A=|-16|$

$A=16$ square units.

Therefore, the area of the triangle is 16 square units.

#Learn more

1. Find the area of the triangle whose vertices are

(2, 3) (-1,0), (2, -4)​

https://brainly.in/question/13478929