Q.5. find the value of p, for which one root of the quadratic equation px 2 – 14x + 8 =0 is 6 times the other.
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let one root of the equation be a then the other is 6a then
Sime of roots is 7a=14/p
then a= 2/p
substitute in the equation then
4/p-28/p+8=0
24=8p
p=3
Sime of roots is 7a=14/p
then a= 2/p
substitute in the equation then
4/p-28/p+8=0
24=8p
p=3
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