Question

Q.5 Find the value of x for the equation:
(2
$(2 + x)(7 - x) \div (5 - x)(4 + x) = 1|$
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Answer 1

Answer:

(2+x)(7-x) ÷ (5-x)(4+x)=1

14+5x -x^2 ÷ 20+x -x^2 =1

14 +5x -x^2= 20+x-x^2

14+5x -x^2-20-x + x^2=0

4x -6=0

x= 6/4= 3/2

Answer 2

Answer:

$\frac{2(7 - x) + x(7 - x)}{5(4 + x) - x(4 + x)} = 1 \\ \\ = \frac{14 - 2x + 7x - {x}^{2} }{20 + 5x - 4x - {x}^{2} } = 1 \\ \\ = \frac{14 + 5x - {x}^{2} }{20 + x - {x}^{2} } = 1 \\ \\ 14 + 5x - {x}^{2} = 20 + x - {x}^{2} \\ \\ 5x - {x}^{2} + {x}^{2} - x = 20 - 14 \\ \\ 4x = 6 \\ \\ x = \frac{6}{4} \\ \\ = \frac{3}{2}$