Question

Q.5 If 5 is a zero of x3 + kx2 + 2x +8 find k.​

Answer 1

Step-by-step explanation:

5+0=X

X=-5

X3+kx2+2x+8=0

-5×3+k×-5×2+2×-5+8=0

-15+(-10k)+(-10)+8=0

-15+(-10k)+(-2)=0

-17+(-10k)=0

-10k=-17

k=-17÷-10