Q-5) In quadrilateral ABCD,
angle A+angle B = 150°, then
angle C + angle D = ...........
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Ans : sum of all angle of quadrilateral is 360°
angle A + angle B = 150° (Given)
let C be X and D be x
A+B+C+D = 360°
150° + X+X = 360°
2X = 360°-150°
2X = 210°
so, C + D = 210°
and C = 105° , D = 105°
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