Math, asked by Anonymous, 4 months ago

Q. 5: Let s denote the semi-perimeter of a triangle ABC in which BC = a, CA = b, AB = c. If a circle touches the sides BC, CA, AB at D, E, F, respectively, prove that BD = s – b.

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Answered by vashutehlan

here the answer pls follow mark BRAINLIEST

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Answered by DynamicPlayer

Heya Ji☃️❤️

According to question, B is external point and BD and BF are tangents and from an external point the tangents drawn to a circle are equal in length. => 2s = AB + AC + BC => 2s = AF+ FB + AE + EC + BD + DC => 2s = 2AE + 2CE + 2BD => s = AE + CE + BD => s = AC + BD => s - b = BD-the-semi-perimeter-of-a-triangle-abc-in-which-bc-a-ca-b-ab-c

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Q. 5: Let s denote the semi-perimeter of a triangle ABC in which BC = a, CA = b, AB = c. If a circle touches the sides BC, CA, AB at D, E, F, respectively, prove that BD = s – b.​

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Heya Ji☃️❤️

Q. 5: Let s denote the semi-perimeter of a triangle ABC in which BC = a, CA = b, AB = c. If a circle touches the sides BC, CA, AB at D, E, F, respectively, prove that BD = s – b.