Q 5
Pls quick I have just 10 mins
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Step-by-step explanation:
let the two digit no be 10x+y. Here x is the tens digit and y is the unit digit .
GIVEN
the unit digit is twice the tenth digit
ie. y=2x----eqn 1
Then if they add 27 to the two digit number the digit gets interchanged
ie. 10x+y+27=10y+x
10x- x +y - 10y+27= 0
9x - 9y +27=0
9(x-y+3)=0
x-y+3=0
x+3=y
Now substitute eqn 1 ie. y=2x
x+3=y eqn --2
x+3=2x
2x-x=3
x=3
now substitute x=3 in x+3=y
x+3=y
3+3=y
y=6
now the digit is 10x+y
substitute x and y here
10×3+6=36
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