Q 5
Solve.
(1) In the adjoining figure,
seg PQ || seg BC,
AP : PB = 3 : 4
If A(OPQCB) = 160,
then find AA ABC).
Answers
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Area of ΔABC = 196 cm² if AP:PB=3:4 , PQ || BC , A(PQCB)=160,then find A(∆ABC)
Step-by-step explanation:
Let say Area of ∆ABC = A
PQ ║ BC
=> ΔAPQ ≈ ΔABC
AP/AB = AP/(AP + PB) = 3/(3 + 4) = 3/7
Area of ΔAPQ / Area of ΔABC = (3/7)²
=> Area of ΔAPQ / Area of ΔABC = 9/49
A(PQCB)= Area of ΔABC - Area of ΔAPQ
=> 160 = Area of ΔABC - (9/49)Area of ΔABC
=> 160 = (40/49)Area of ΔABC
=> Area of ΔABC = 196 cm²
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