Question

Q 5
Solve.
(1) In the adjoining figure,
seg PQ || seg BC,
AP : PB = 3 : 4
If A(OPQCB) = 160,
then find AA ABC).​

Answer 1

Area of  ΔABC = 196 cm² if AP:PB=3:4  , PQ || BC , A(PQCB)=160,then find A(∆ABC)

Step-by-step explanation:

Let say Area of ∆ABC = A

PQ ║ BC

=> ΔAPQ ≈ ΔABC

AP/AB  =  AP/(AP + PB)  =  3/(3 + 4) = 3/7

Area of  ΔAPQ  / Area of  ΔABC =  (3/7)²

=> Area of  ΔAPQ  / Area of  ΔABC = 9/49

A(PQCB)= Area of  ΔABC - Area of  ΔAPQ

=> 160 =  Area of  ΔABC - (9/49)Area of  ΔABC

=> 160 = (40/49)Area of  ΔABC

=> Area of  ΔABC = 196 cm²

Learn more:

The area of a triangle ABC is 10.8 cm2.if CP=PB and 2AQ= QB the ...

brainly.in/question/8990985

AP is perpendicular to BC . PC is greater than PB .PQ is equal to PB ...

brainly.in/question/12109623