Q.5. Solve the following by regrouping the numbers using distributive property.
a. 101×3 c.23×12 e.45×9
b.99×6 d. 33×11 f.47×62
Answers
Answered by
4
Step-by-step explanation:
1; (100×3)+(1×3)
300+3
303
3; (20×10)+(3×2)
200+6
206
5; (40×9)+(5×9)
360+45
405
2; (90×6)+(9×6)
540+54
594
4; (30×10)+(3×1)
300+3
300
6; (40×60)+(7×2)
2400+14
2414
Answered by
6
Answer:
a .
101 ×(2+1)
= 101 ×2+101×1
=202+101
=303.
c.
23×(10+2)
=23×10+23×2
=230+46
=276.
e.
45×(6+3)
=45×6+45×3
=270+135
=405
b.
99×(4+2)
=99×4+99×2
=396+198
=594.
d.
33×(10+1)
=33×10+33×1
=330+33
=363
Step-by-step explanation:
f
47×(60+2)
=47×60+47×2
=2820+94
=2914.
Similar questions