Question

Q 5 - The angle of a triangle are 3xº, (2x-7) and (4x-11)". The value of x is :​

Answer 1

Step-by-step explanation:

sum of all the angles of the triangle=180

3x+2x-7+4x-11=180

9x-18=180

dividing throughout by 9,we get

x-2=180

x=20+2

x=22

therefore,3x=3*22=66degree

2x-7=2*22-7=37degree

4x-11=4*22-11=81degree

Answer 2

Solution:

Let the angles of a triangle be ∠ A , ∠B and ∠C

where :

∠A = 3x°

∠B = (2x-7)°

∠C = (4x-11)°

We know that

The sum of the angles of a triangle is 180°

Then ,

∠ A+∠ B+∠C = 180°

Now , put the given values

$\sf\implies\:3x+2x-7+4x-11=180\degree$

$\sf\implies\:(3x+2x+4x)+(-7-11)=180\degree$

$\sf\implies\:9x-18=180\degree$

$\sf\implies\:9x=180+18$

$\sf\implies\:9x=198$

$\sf\implies\:x=\dfrac{198}{9}$

$\sf\implies\:x=22$

Hence ,

∠A = 3x = 66

∠B = 2x-7 = 37

∠C =4x-11 = 77