Math, asked by mishyammy, 4 months ago

Q.5. The average time a subscriber spends reading the Time of India is 49 minutes. Assume the standard deviation is 10 minutes and that the times are normally distributed. (a) What is the probability a subscriber will spend at least 1 hour reading the Journal? (b) What is the probability a subscriber will spend between 30-40 minutes reading the Journal? (c) For the 10% who spend the most time reading the Journal, how much time do they Spend?

Answers

Answered by Anonymous
1

Answer:

Your answer is in the attachment

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Answered by gunu97896
1

Answer:

Step-by-step explanation:

They spend at least 69.48 minutes reading the paper.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean  and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

For the 10% who spend the most time reading the paper, how much time do they spend?

They spend at least X minutes, in which X is the value of X when Z has a pvalue of 0.90. So it is X when Z = 1.28.

They spend at least 69.48 minutes reading the paper PLEASE MARK ME AS BRILLIANT

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