Question

Q.5
The magnitude of the linear acceleration, the particle
moving in a circle of radius of 10 cm with uniform speed
completing the circle in 4 s, will be​

Answer 1

Required Solution :-

• Radius of circle is 10 cm
• Time in which particle is completing the circle is 4 seconds.

As we know that distance covered by the particle would be the circumference of the circle.

Therefore,

• Distance (d) = 2πr
• Distance (d) = 2 × 22/7 × 10
• Distance (d) = 62.8

Now, calculating the linear speed as we know that,

• v = 2πr / t

Here,

• v is linear speed
• r is radius
• t is time taken

Here we'll be applying the values but value of '2πr" is "62.8" we'll substitute it here !

• v = 62.8 / 4
• v = 15.7 cm/s

As we all know that if the acceleration of the particle is towards the centre then the magnitude of acceleration us calculated by the formula :

• a = v² / r

Here,

• v is linear speed
• r is radius

Therefore, substituting the values :

• a = (15.7)² / 10
• a = 246.49 / 10
• a = 24.649 cm/s²

Therefore, magnitude of linear acceleration is 24.649 cm/s²