Question

Q. 5. The mass of the earth is 6x1024 kg and its mean
radius is 6400x109 m. If your mass is 40 kg, find the attraction
between you and the earth.
12279​

Answer 1

Answer:

hloo..

.

Given,

Maas of planet = 6*10^24 kg

Radius of planet = 6.4*10^6 m

G = 6.7*10^-11 Nm^2/kg^2

As we know that,

g = (G*m)/r^2

or, g = {(6.7*10^-11)*(6*10^24)}/(6.4*10^6)^2

or g = 9.81 meter per second square

.

please mark as brainlist..

Answer 2

Answer:

6.51 × 10⁻¹⁰ N

Explanation:

Given :

m₁ = 6 × 10²⁴ kg

m₂ = 40 kg

r = 6400 × 10⁹ m

We have to find force of attraction F :

We know :

F =  G m₁ m₂ / r²

Putting values here we get :

= > F = ( 6.67 × 10⁻¹¹ ) . ( 6 × 10²⁴ ) . ( 40 ) / ( 6400 × 10⁹ )² N

= >  F = ( 6.67 ) . ( 6 × 10⁻¹³ ) . ( 40 ) / ( 64 × 10¹¹ )² N

= > F = ( 6.67 ) . ( 6 × 10⁻¹³ ) . ( 40 ) / ( 64 )² × 10²² N

= >  F = ( 6.67 ) . ( 6 × 10⁻⁸ ) . ( 4 ) / ( 64 )² N

= > F = 26.68 × 10⁻⁸ / 4096 N

= > F = 26680 × 10⁻¹⁰ / 4096 N

= > F = 6.51 × 10⁻¹⁰ N

Hence we get required force!