Question

Q 5. The relative humidity (in %) of a certain city for 15 days was as follows: 2 90.3 95.3 92.9 94.2 89.2 92.3 93.5 92.7 95.1 93.3 95.2 92.1 90.2 88.7 93.5 Construct a grouped frequency distribution table with classes 88 - 90, 90-92, etc.​

Answer 1

Step-by-step explanation:

i) A grouped frequency distribution table of class size 2 has to be constructed.

The class intervals will be -84 - 86, 86 - 88, and -99 - 90...

By observing the data given above, the required table can be constructed as follows.

Relative Humidity (in %) Number of days (frequency)

84 - 86 1

86 - 88 1

88 - 90 2

90 - 92 2

92 - 94 7

94 - 96 6

96 - 98 7

98 - 100 4

Total 30

ii) It can be observed that the relative humidity is high. Therefore, the data is about a month of rainy season.

iii) Range of data

= Maximum value - Minimum value

= -99.2 + 84.9

= -14.3