Question

Q.5. The sum of two numbers is 45 and their ratio is 7:8. Find the numbers?

Answer 1

let the required no. be 7x and 8x
then,


$7x + 8x = 45 \\ \\ 15x = 45 \\ \\ x = \frac{45}{15} \\ \\ x = 3 \\ \\ \\ \\ now \: 7x = 7(3) = 21 \\ \\ \: \: \: \: \: \: \: \: \: 8x = 8(3) = 24 \\ \\ \\ here \: we \: got \: the \: required \: no.$
e.i., 21 and 24 and their sum is 45







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