Question

Q.5: Which term of the A.P. 3, 15, 27, 39, … will be 132 more than its 54th term?​

Answer 1

Answer:

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Question :-

Which term of the A.P. 3, 15, 27, 39, … will be 132 more than its 54th term?

Answer:-

Step-by-step explanation:

Given:-

Ap = 3,15,27,39

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Solution :-

• Let us find the 54th term of the ap

By the equation

• an= a+(n-1)d

a = 3,d = 12,n = 54

• an = 3*53*12 = 639
• a54 = 639

So, nxt let us find the 132 more than 639 term

• So, the Term would be 649+132 = 771

Let us take n = 771 so solving it we get

• an = 3+(n-1)*12( do the calculated )

• n-1 = 768/12

• n-1= 64

• Therefore n = 64+1 = 65

So the required term is 65th

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Answer 2

Let us find the 54th term of the ap

By the equation

an= a+(n-1)d

a = 3,d = 12,n = 54

an = 3*53*12 = 639

a54 = 639

So, nxt let us find the 132 more than 639 term

So, the Term would be 649+132 = 771

Let us take n = 771 so solving it we get

an = 3+(n-1)*12( do the calculated )

n-1 = 768/12

n-1= 64

Therefore n = 64+1 = 65

So the required term is 65th

Answer 3

Let us find the 54th term of the ap

By the equation

an= a+(n-1)d

a = 3,d = 12,n = 54

an = 3*53*12 = 639

a54 = 639

So, nxt let us find the 132 more than 639 term

So, the Term would be 649+132 = 771

Let us take n = 771 so solving it we get

an = 3+(n-1)*12( do the calculated )

n-1 = 768/12

n-1= 64

Therefore n = 64+1 = 65

So the required term is 65th