Q.5. Write the smallest number which is divisible by both 306 and 657
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Answered by
1
Answer:
The answer is 22338.
Hope it helps you.
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Answered by
1
Answer:
Basically we need to find LCM of 306 and 657 for getting smallest number divisible by both the numbers.
Step-by-step explanation:
Prime Factorisation of 306= 2× 3²×17
prime Factorisation of 657= 3×3×73
Now LCM of 306 and 657=2×3×3×17×73
=2 × 9 × 17 × 73
= 306 × 73
= 22338
Therefore, the smallest number divisible by is 306 and 657 is 22338
Hope it helps u
Thankew
by Hibba
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