Question

Q. 5 years ago, the average age of A,B, C and D was 45. With E joining them now, the average of all the five is 49 years. How old is E: (a) 42 years (b) 45 years (c) 47 years (d) 49 years n​

Answer 1

Answer:

{(a-5)+(b-5)+(c-5)+(d-5)}=45×4=180

a+b+c+d=20+180=200 equation 1

a+b+c+d+e=49×5=245 equation 2

subtract equation 1 from equation 2, you will get

e=245-200=45=age of E Ans