Question

Q.56
The reaction A+B C + D is studied in
a one litre Vessel at 250°. The initial
concentration of A was 3n and B was n. After
equilibrium was attained then equilibrium
concentration of C was found to be equal to
equilibrium concentration of B. What is the
concentration of D at equilibrium -
(1)
(2) ( 30 - 2
(4) n

Answer 1

Answer:

A+B=7++*289544927

Answer 2

The concentration of D at equilibrium is $\frac{n}{2}$

Explanation:

Initial concentration of A= 3n

Initial concentration of B= n

The given balanced equilibrium reaction is:

                          $A+B\rightleftharpoons C+D$

Initial conc            3n       n        0     0  

At eqm. conc.    (3n-x) M   (n-x) M   (x) M     (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[C]\times [D]}{[A]\times [B]}$

Now put all the given values in this expression, we get :

$K_c=\frac{x\times x}{(3n-x)\times (n-x)}$

We are given : at eqm $[C]=[B]$

$x=(n-x)$

$x=\frac{n}{2}$

Thus concentration of D at equilibrium , $[D]=x=\frac{n}{2}$

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