Question

Q.6. 1.2 g of Mg was dropped in 100 mL of 0.1 M HCl solution.Calculate the volume of H2 obtained by STP. mol of Mg left behind

Answer 1

Answer:

Answer

Mg+H

2

SO

4

→MgSO

4

+H

2

1.2 g Mg reacts with 0.05 mol H

2

SO

4

.

H

2

SO

4

taken =100 mL of 1 M H

2

SO

4

=0.1 mol.

H

2

SO

4

left =0.1−0.05=0.05 mol in 100 mL solution.

[H

2

SO

4

] = 0.05 × 10=0.5 M.