Question

[Q. 6] A cook used a fire tong of length 28 cm to lift a piece of burning coal of mass 250 g. If he applies the effort at a distance of 7 cm from the fulcrum, find the effort. (Take g=10 ms-2).
(a) 20 N (b) 10 N c) 30 N d) 25 N​

Answer 1

Answer:

[Q. 6] A cook used a fire tong of length 28 cm to lift a piece of burning coal of mass 250 g. If he applies the effort at a distance of 7 cm from the fulcrum, find the effort. (Take g=10 ms-2).

(a) 20 N (b) 10 N c) 30 N d) 25 N

→b) 10 N

Given load =250gf, load arm =28cm,

effort arm = 7cm and effort =E.

Now, load × load arm = effort × effort arm

250×28=E×27

E=

7

250×28

=1000gf=1kgf or 10N

Answer 2

Answer:

Length of the tongs L=28

Length at effort apply, l=14

Moment of effort=Moment of applied force

F×14=  250/1000×g×28

⇒F=0.25×10×2=5N.