Question

Q.6 A copper block of mass 2 kg is heated to a temperature of 500°C and then placed in a large
block of ice at 0°C. What is the maximum amount of ice that can melt? The specific heat of
copper is 400 J kg °C and latent heat of fusion of ice is 3.5 x 105 J kg
(A) 4/3 kg
(B) 6/5 kg
(C) 8.7 kg
(D) 10/9 kg
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Answer 1

Answer:

Explanation:

MATE HERE IS YOUR ANSWER

2×400×500=m×3.5×10⁵

400000=m×3.5×10⁵

m=400000/3.5×10⁵

m=400000/350000

m=40/35

m=8/7 kg

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Answer 2

Explanation:

The Copper block to have temperature 0 degree C

has to liberate heat 2 × 400 × 500 joule = 4 × 10^5

Joule.

Next if m kg of ice melts , it gains heat energy

equal to 3•5 × 105 m = (35 × 105)/10 × m

From Calorimetry,

( 35 × 105)/10 ×m = 400000

or m = 4000000 ÷ 3675 = 1088•435 kg.