Question

Q-6 A current of 1 A flow
through a resistor of 10 columb for 2sec.Heat produce through it is
20J
40J
10J
15 J​

Answer 1

Answer:

Explanation:

Heat produced , H=I  

2

Rt

here,  

t

H  

5

​

 

​

=I  

5

2

​

R  

5

​

=10⇒I  

5

​

=  

5

10

​

 

​

=  

2

​

 . This is the current through resistor 5Ω.

Voltage across  resistor 5Ω is V  

5

​

=I  

5

​

R  

5

​

=  

2

​

×5=5  

2

​

V

As resistors (4,6) and 5 are in parallel, so potential across (4,6) is equal to V  

5

​

.

As resistor 4 and 6 are in series so current through each resistor I  

4

​

=I  

6

​

=  

4+6

V  

5

​

 

​

=  

4+6

5  

2

​

 

​

=  

2

2

​

 

​

 

Heat produce in resistor 4 per sec =I  

4

2

​

R  

4

​

=(  

2

2

​

 

​

)  

2

×(4)=2cal/sec