Question

Q.6. A group of boys in a village, bought a football costing Rs 121. If each boy contributed as many 25 paise-coins as there were boys, find the number of boys.


Q7. Find the sum of the first 11 odd no.s and also find the square root of the sum.


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Answer 1

Answer:

Q6. Soln: The cost of the football = Rs. 121 = 12100 paise.

According to the question, each boy contributed as many 25 paise coins as there were boys.

∴ The number of boys =

$\sqrt{ \frac{12100}{25} } = \frac{110}{5} = 22$

Q7. Soln: The first eleven odd numbers are:

1, 3, 5, 7, 9, 11, 13, 15, 17, 19 and 21.

Their sum = 1+3+5+7+9+11+13+15+17+19+21 = 121.

And it's square root =

$\sqrt{121} = 11$

Hope it's help u

Answer 2

Answer:

• A group of boys in a village bought a football costing Rs 121. If each boy contributed as many 25 paise-coins as there were boys, then the number of boys is 484.
• The sum of the first 11 odd no.s is 121 and the square root of the sum is 11.

Step-by-step explanation:

6) Cost of ball= rs121

Contribution of each boy =25p=Rs0.25=Rs1/4

Cost of ball = no of boys × their contribution

Hence, no of boys = cost of ball / each contribution

No of boys = 121 ÷ 1/4 = 121×4/1 =484

7) 11 odd numbers are 1,3,5,7,9, 11,13, 15, 17, 19, 21.

Sum of odd 11 numbers = 1+3+5+7+9+11+13+15+17+19+21=121

And $\sqrt{121} = 11$