Math, asked by aarthyarty22, 4 days ago

Q.6) A man has 500 kg of mangoes, part of which he sells at 10% profit and the rest at 20% profit. He gains 14% on the whole. The quantity sold at 20% profit is.

Answers

Answered by Sheg
0

Answer:

200 kg

Step-by-step explanation:

Assume he sold x kg at a profit of 10%

Rest (500-x) he sold at a profit of 20%.

Here, I have used alligation to determine the required ratio.

Lower profit. Higher Profit

10 20

14

6(=20-14) 4 (=14-10)

Therefore, the following relationship must hold true

 \frac{x}{500 - x}  =  \frac{6}{4}

 \frac{x}{500 - x}  =  \frac{3}{2}

2x = 1500 - 3x

=> 5x = 1500

=> x = 300

Quantity sold at a profit of 20% = 200 kg (=500-300)

Answered by amruthachandran2898
0

Answer:

200 kg

Step-by-step explanation:

A man has 500 kg of mangoes, part of which he sells at 10% profit and the rest at 20% profit. He gains 14% on the whole. The quantity sold at 20% profit is.

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