Question

Q(6) A particle initially at rest moves with an acceleration 5 m/sec? find the distance travelled in (a) 6sec (b) 7 sec (c) 7 second​

Answer 1

Formula to find distance in this case is

1/2 at square

a. Given,a=5m/sec

t=6 sec

Therefore,1/2*5*36 = 90 m

b. Given,a =5m/sec

t=7sec

Therefore,1/2*5*49=122.5 m

c is as b