Question

Q(6) A particle initially at rest moves with an acceleration 5 m/sec? find the distance travelled in (a) 6sec (b) 7 sec (c) 7 second​

Answer 1

Answer:

90 m and 122.5 m

Explanation:

Answer 2

Answer:(a)90m and (b) 122.5m

EXPLAINATION: (a)HERE,u=0m/s;a=5m/sec²;t=6sec

BY SECOND EQUATION OF MOTION WE KNOW THAT ...s=ut+1/2at²

s=(0×6)+1/2×5×(6)²

=0+90

=90m

(B)HERE,u=0m/s;a=5m/s²;t=7seconds

AGAIN BY SECOND EQUATION OF MOTION ,

s=(0×7)+1/2×5×(7)²

=0+122.5

=122.5m

HOPE IT HELPS

PLZ ADD ME AS A BRAINLIST

THANKU ✌✌