Question

Q.6. A platinum wire ring of radius 2.5 cm floats horizontally on the surface of water.
A vertical force of 0.022 N is required to detach the ring from the surface of
water. Find surface tension of water.​

Answer 1

$\huge\underline{\underline{\bf \orange{Question-}}}$

A platinum wire ring of radius 2.5 cm floats horizontally on the surface of water. A vertical force of 0.022 N is required to detach the ring from the surface of water. Find surface tension of water.

$\huge\underline{\underline{\bf \orange{Solution-}}}$

$\large\underline{\underline{\sf Given:}}$

• Radius (R) = 2.5cm ➝ 0.025m
• Force (F) = 0.022N

$\large\underline{\underline{\sf To\:Find:}}$

• Surface Tension of water (S)

$\large{\rm We \: Know \: That-}$

✪$\large{\boxed{\bf \blue{S=\dfrac{F}{2πR}}}}$

$\implies{\sf \dfrac{0.022}{2×3.14×0.025} }$

$\implies{\sf \dfrac{0.022}{0.157} }$

$\implies{\bf\red{Surface\: Tension ( S)=0.14 N/m}}$

$\huge\underline{\underline{\bf \orange{Answer-}}}$

Surface Tension of water is ${\bf \red{0.14\:N/m}}$.