Q.6) A student places a pile of coins on a table, as shown in Fig. 6.1. There are 8 coins in the pile. The weight of each coin is 0.036 N. The area of each coin is 0.0013 m². Calculate the pressure on the table caused by the pile of coins ? Fig. 6.1. [3] Pressure
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Answer:
221.5Pa
Explanation:
given,
weight of one coin = 0.036N
no:of coins = 8
base area of each coin = 0.0013m²
Force on table = total weight of coins
= 8 × weight of each coin
= 8 × 0.036 = 0.288N
pressure = (force exerted)/(area)
= (0.288)/(0.0013)
≅ 221.5 Pa
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