Question

А
Q.6 a) The uniform 18 kg
bar OA is held in position
shown in Fig. 8 by the
smooth pin at O and the
cable AB.
Determine the
tension T in the cable and the
magnitude and direction of
the external pin reaction at O.
[7]
1.2 m
60°
B
Ho
1.2 m​

Answer 1

Explanation:

Let us find the angle made by AB with respect to horizontal

It is given by

tanθ=OAsin60BO+OAcos60=0.666⟹θ=33.67o

Now tension in cable AB acts along AB

Thus angle AB makes with OA = 180 - 120 - 33.67 = 26.33...