Q.6 A triangle has sides 25. 39. 34 units. If the area of a square exceeds the area of this triangle by 21 units, then the side of
the square is:
Answers
Answer:
SOLUTION
Given:
Sides of triangle are 25, 39 and 34 units.
Area of square is more than that of triangle = 21 units
Formula:
Area of triangle = √[s (s – a) (s – b) (s – c)]
s = (a + b + c)/2
Perimeter of the triangle = a + b + c
Calculation:
a = 25, b = 39 and c = 34
S = (25 + 39 + 34)/2
⇒ S = 98/2 = 49 unit
Area of triangle ⇒
⇒ √[49 (49 – 25) (49 – 39) (49 – 34)
⇒ √[49 × 24 × 10 × 15]
⇒ √(7 × 7 × 2 × 2 × 2 × 3 × 2 × 5 × 3 × 5)
⇒ 7 × 2 × 2 × 3 × 5
⇒ 420
Area of square = 420 + 21 = 441
∴ Side of square = √441 = 21 unit
Answer:
SOLUTION
Given:
Sides of triangle are 25, 39 and 34 units.
Area of square is more than that of triangle = 21 units
Formula:
Area of triangle = √[s (s – a) (s – b) (s – c)]
s = (a + b + c)/2
Perimeter of the triangle = a + b + c
Calculation:
a = 25, b = 39 and c = 34
S = (25 + 39 + 34)/2
⇒ S = 98/2 = 49 unit
Area of triangle ⇒
⇒ √[49 (49 – 25) (49 – 39) (49 – 34)
⇒ √[49 × 24 × 10 × 15]
⇒ √(7 × 7 × 2 × 2 × 2 × 3 × 2 × 5 × 3 × 5)
⇒ 7 × 2 × 2 × 3 × 5
⇒ 420
Area of square = 420 + 21 = 441
∴ Side of square = √441 = 21 unit