Question

Q.6. A truck starts from rest and rolls down a hill with a constant acceleration. It travels a
distance of 400m in 20 seconds. Find its acceleration. Find the force acting on it, if its mass
is 7 tonne. (1 tonne = 1000 kg)​

Answer 1

Answer:

Explanation:

Hope this will help you....

Answer 2

Answer:

Acceleration,a = 2ms^-2

Force,f = 1400N

Explanation:

Given :

Initial velocity of the truck,u => 0 [Since truck starts from rest]

Distance travelled,s => 400m

Time taken,t => 20s

Mass,m => 7 tonnes = (7 × 1000)kg = 7000kg

To Find :

Accelaration,a => ?

Force,f => ?

Solution :

We know that :-

\rm{s=ur+\dfrac{1}{2}at^2

\rightarrow\rm{400m=0\times 20s+\dfrac{1}{2}\times a\times(20)s^2

\rightarrow \rm{400m=0+\dfrac{1}{2}\times a\times400s^{2}

\rightarrow\rm{}400m=\dfrac{1}{1}\times a\times 200s^2→400m=

1

1

×a×200s

2

\rightarrow\rm{400m=a\times200s^2}→400m=a×200s

2

\rightarrow \rm{a=\dfrac{400m}{200s^2}

\rightarrow\rm{a=2ms^{-2}}→a=2ms

−2

Force = m × a

⇒ F = 7000kg × 2ms^-2

⇒ F = 1400N