Question

Q.6. An electric field along the x-axis is given by Ē = 100 i N/C for x > 0 and Ē=-100 i N/C for
x<0. A right circular cylinder of length 20 cm and radius 5 cm lies parallel to the x-axis with its
centre at the origin and one face at x = +10 cm, the other face at x = -10 cm. Calculate the net
outward flux through the cylinder.​

Answer 1

Answer:

answer is 9

Explanation:

Answer 2

Thus the net outward flux through the cylinder is Φ = 6.28 E r^2 N m^2 / C^-1

Explanation:

We are given that:

• Electric field  E = 100 i N/C     [ For x > 0]
• Electric field Ē = -100 i N/C       [ For x< 0 ]
• Radius = 5 cm
• Length = 20 cm

Solution:

E and ΔS are parallel to each other.

Φ = E.ΔS + E.ΔS

Φ = Ex (πr^2 ) +  Ex (πr^2 )

Φ = 2 Ex  (πr^2 ) N m^2 / C^-1

Net charge n cylinder:

Φ = 2 Ex  (πr^2 )  

Φ = 6.28 E r^2 N m^2 / C^-1

Net charge on cylinder as per gauss law is given by:

Φ = 8.854 x 10^-12 x 3.12 x Exr^2

Φ = 27.8 x 10^-12 Exr^2