Q.6 Consider an arrangement in which a solution containing 20 g of hemoglobin in one liter of the solution is placed in the right compartment and a pure water is placed in the left compartment. At equilibrium, the height of water in the right column is 77.8 mm in excess of the height of the solution in the left column. What is the molar mass of hemoglobin? T = 298 K and density of solution is 1 x 103 kg.m-3?
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6.49×10
7
gmol
−1
Let M g/mol be the molar mass of haemoglobin.
Number of moles of haemoglobin =
Mg/mol
20g
=
M
20
mole. The volume of the solution is 1 dm
3
or 1 L.
The molarity of the haemoglobin solution is C=
1L
M
20
mol
=
M
20
M
The osmotic pressure Π=
76.0cm×13.595g/cm
3
×981m/s
2
7.78cm×1g/cm
3
×981m/s
2
=0.00753 atm.
The osmotic pressure Π=CRT
0.00753atm=
M
20g
mol/L×0.08206Latm/molK×298K
M=6.49×10
4
g/mol
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