Q.6 Determine an expression due to long straight current
carrying wire at a point with the help of Biot-Savert law.
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Explanation:
Magnetic induction due to infinitely long straight conductor carrying current: XY, is an infinitely long straight conductor carrying a current I(Figure).
P is a point at a distance a from the conductor. AB is a small element of length dl. θ is the angle between the current element Idl and the line joining the element dl and the point P. According to Biot-Savart law, the magnetic induction at the point P due to the current element Idl is.
AC is drawn perpendicular to BP from A.
∠OPA=ϕ, ∠APB=dϕ
In ΔABC, sinθ=
AB
AC
=
dl
AC
∴AC=dlsinθ ..........(2)
From ΔAPC, AC=rdϕ .........(3)
From equations (2) and (3),
rdϕ=dlsinθ ............(4)
Substituting equation (4) in equation (1)
dB=
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