Question

Q(6) Evaluate (cos4A- sinA).
$cos ^4a - sin ^4a$
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Answer 1

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The solution is in the attachment.

Note

$\sin( { \alpha }^{2} ) + { \cos( \alpha ) }^{2} = 1$

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Answer 2

Step-by-step explanation:

cos⁴a-sin⁴a

(cos²a)²-(sin²a)² ....... a²-b²

(cos²a-sin²a)(cos²a+sin²a). ..........cos²a=1-sin²a

(1-sin²a-sin²a)(1)

(1-2sin²a)

this question was asked in periodic test

this is correct answer