Question

Q-6. Explain the action of dilute hydrochloric acid on the following with

chemical equation:
(i) Magnesium ribbon.
(ii) Sodium hydroxide.
(iii) Crushed egg shells.​

Answer 1

Answer:

(i) Mg + 2HCI → MgCl2 + H2 Hydrogen gas is produced. (ii) HCl + NaOH→ NaCl + H2O Neutralisation reaction (iii) 2HCl(aq) + CaCO3(s)→CaCl2 (aq)+ H2O + CO2 Read more on Sarthaks.com - https://www.sarthaks.com/89631/explain-action-dilute-hydrochloric-acid-following-chemical-equation-magnesium-ribbon

Explanation:

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Answer 2

Answer:

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Explanation:

(i) Hydrogen gas will be formed Mg(s) +2HCl (dil)→ MgCl2(aq) +H2(s)

(ii) Sodium chloride and water will be formed NaOH +HCl→ NaCl +H2O

(iii) Crushed egg shell are made up of CaCO3 Which reacts with HCl to give brisk effervescence due to CO2

CaCO3(s) +2HCl→ CaCl2 +H2O +CO2