Question

Q 6 : find the area of the cardboard required to make a closed box with length 0.4 m , breadth 35 cm and height
15 cm.​

Answer 1

$\mathbb{\huge{\purple{HEY\:MATE}}}$

Just square and add them ...finally multiply by 2

Answer 2

T.S.A OF CUBOID (lb+bh+hl)

0.4m to cm

= 40cm

2(40x35 + 35x15 + 15x40)

=5050cm²