Math, asked by ravindraagarwal509, 11 months ago

Q.6 How many numbers with two or more digits can be formed with the digits
1,2,3,4,5,6,7,8,9, so that in every such number, each digit is used at most once and the
digits appear in the ascending order?​

Answers

Answered by chhabhaiyanakul007
0

Answer:

There are in total 9 digits so total numbers that can be made is

= 1+9+36+84+126+126+84+36 = 502

Step-by-step explanation:

Total digits is 9

But minimum two digit number is accepted

use combination 9C9+9C8+8C7+9C6+9C5+9C4+9C3+9C2

Answered by SidhantVerma77
0

Answer:

The total numbers that can be made using these numbers is 205.

Step-by-step explanation:

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