Question

Q.6. If p and q are the
zeroes of the polynomial
p(x) = x²+x+1,then 1/p+1/q=​

Answer 1

Step-by-step explanation:

Given quadratix polynomial is x2 −6x + k

Since α, β are zeroes of the given polynomial, we have

Sum of roots (α+ β) = − (b/a) = − (−6/1) = 6

Prouduct of roots (αβ) = (c/a) = (k/1) = k

Given (α+β)2+ 2αβ = 40

⇒ 62 + 2(k) = 40

⇒ 36 + 2k = 40

⇒ 2k = 40 − 36 = 4

∴ k = 2