Question

Q.6) In AABC, I(AC) = 8.5 cm, m ZABC = 90°. (BC) = 6.5 cm.​

Answer 1

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In AABC, I(AC) = 8.5 cm, m ZABC = 90°. (BC) = 6.5 cm?

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To construct:

△ABC in which AB=2.5cm,BC=6cm and AC=6.5cm

Steps of construction:

(a) Draw a line segment BC=6cm

(b) Taking B as centre and radius 6.5cm, draw another ar

c) which intersects first arc at point A

(d) Join AB and AC

(e) Measure angle B with the help of protractor.

It is the required △ABC and ∠B=80 o

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Answer 2

Answer:

Steps of constructions:

(1) Draw seg QR of length 4.2 cm.

(2) Draw ray QT such that ∠RQT = 40°.

(3) Mark point S on ray QT such that QS = 8.5 cm

(4) Draw seg RS.

(5) Construct the perpendicular bisector of seg RS .

(6) Name the point of intersection of ray QS and the perpendicular bisector of RS as P.

(7) Draw seg PR.

Therefore, △ABC is the required triangle