Q.6) In ABC, mzABC = 90° and seg
BD I side AC. AD = 18 and DC = 8
then, find the values of BD and AB.
(Match the pair.)/AABC मध्ये, mZABC
= 90° व रेख BD | बाजू AC.AD = 18 आणि
DC = 8 तर BD आणि AB च्या किंमती काढा.
(जोड्या जुळवा.)
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Answer:
Given, BD = 8 cm, AD = 4 cm, ∠ABC = 90° and BD⊥AC.
we know that ,If a perpendicular is drawn from the vertex containing a right angle of a right triangle to the hypotenuse then the triangle on each side of the perpendicular are similar to each other and to the whole triangle.
So, ΔDBA∼ΔDCB (A-A similarity)
BD/CD = AD/BD
[Since, triangles are similar, hence corresponding sides will be proportional]
BD² = AD x DC
(8)² = 4 x DC
64 = 4DC
DC = 64/4
DC = 16
Hence, the length of CD is 16 cm..
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