Question

Q.6. In Fig. 1, if CD = 2 (BC), find angle BAD.​

Answer 1

Answer: ∠BAD = 60°

Step-by-step explanation has been provided in the following attachment. I hope this helps you. Kindly reply back if there's any problem with this answer. Have a great day! :D

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Answer 2

The value of angle BAD is 60°

Step-by-step explanation:

here , BC = 10 m

and given that CD = 2(BC)

therefore , CD = 2(10) = 20 m

then BD = BC+CD = 10+20 = 30 m

AB = 10√3 m

in triangle ABD

tan A = $\frac{BD}{AB}$

tan A = $\frac{30}{10\sqrt{3} }$

tan  A= $\frac{3}{\sqrt{3}}$

on rationalising we get

$\tan A = \frac{3}{\sqrt{3} }\times \frac{\sqrt{3}}{\sqrt{3}} = \frac{3\sqrt{3}}{3}= \sqrt{3}$

thus

$\tan A = \sqrt{3}\\\\\tan A = \tan 60^\circ\\\\A= 60^\circ$

Hence , The value of angle BAD is 60°

#Learn more:

Qadrilateral ABCD is a rhombus . Then prove that

( AB )^2 + ( BC )^2 + ( CD )^2 = 2 × CD × AD

https://brainly.in/question/4148896