Q.6 In heither magnitude nor in direction In cycle wheel of radius 0.4 m completes one revolution in one second, then acceleration of the cycle is ?
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Answer:
Centripetal acceleration =4π
2
n
2
r
where n is number of revolution and r is radius
Centripetal acceleration =4π
2
n
2
r=4π
2
×(1)×0.4=1.6
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